BENNIEWASHERE

There was a challenge, it goes like this:  "Given a string containing only the characters x and y , find whether there are the same number of x s and y s." This is what I did:     // Given a string containing only the characters x and y, find whether there     // are the same number of x's and y's.     public boolean balanced(String s) {         int x = 0, y = 0;         for (int i = 0; i < s.length(); i++)             if (s.charAt(i) == 'x')                 x++;             else if (s.charAt(i) == 'y')                 y++;         if (x == y)             return true;     ...

There is this awesome subreddit called r/dailyprogrammer, that posts programming challenges. There was this post about additive persistence . The challenge goes like this: Take an integer N: Add its digits Repeat until the result has 1 digit The total number of iterations is the additive persistence of N.  This is what I did: 1.    public int calculate(int n){ 2.        int c = 0; 3.        while(n > 9){ 4.            c++; 5.            String s = n + ""; 6.            n = 0; 7.            for (int i = 0; i < s.length(); i++) 8.                n += Integer.parseInt(s.charAt(i) + ""); 9.        } 10.       return c; 11.   } This is how it Work...